We've submitted two composite parts:
1. Part:BBa_K3478891 , p15A-Lac UV5-atoB-HMGS-HMGR-Trc-MK-PMK-PMD-idi
2. Part:BBa_K3478889, pTAC-GPPs-bLIS
We've used and added information two composite parts:
1. Part:BBa_K3166057 , AtoB-HMGS-tHMGR
2. Part:BBa_K3166056 , MK-PMK-PMD-Idi
1. p15A-Lac UV5-atoB-HMGS-HMGR-Trc-MK-PMK-PMD-idi Part:BBa_K3478891
Description
p15A is a composite part composed of vector p15A and MVA pathway including coding atoB, HMGS, HMGR, MK, PMK, and PMD, a combination of the composite parts BBa_K3166057 and BBa_K3166056. The MVA pathway expressed by this part can produce DMAPP from Acetyl-CoA. DMAPP is a subtract for GPPS, which are important in linalool synthase in our project. We used PCR to amplify MVA-1 and MVA-2 which is two fragments of p15A-MVA (figure 1 A) and then purified it (figure 1 B).
we used Gibson assembly to construct the two gene fragments into a plasmid, and then transformed it into E. Coli DH5α. We sent the bacteria to a biotech company which helped us to do gene sequencing. The result of the gene sequencing indicates that we successfully constructed the composite part p15A-MVA. (figure 2)
We cotransformed p15A-MVA and pR6K-ptac-GPPS-bLIS to E. Coli DH5α. and pR6K-ptac-GPPS-bLIS is a part that produce GPP synthase and linalool synthase that produces linalool. the substrate of GPP synthase is DMPP. Therefore, the MVA pathway regulated by p15A-MVA provides substrates for GPPS, which allows linalool synthesis to occur. We used IPTG to induce bacteria cotransformed to E. Coli DH5α with15A-MVA and pR6K-ptac-GPPS-bLIS, and produced linalool
2. pR6K-pTAC-GPPS-bLIS Part:BBa_K3478889
Description
GPPS-bLIS is composed of two coding sequences, GPPS and bLIS. Coding GPPS is used to produce Geranyl pyrophosphate synthase that produce GPP from DMAPP, which is a substrate for linalool synthase that produces linalool. in our experiment, we constructed pR6K-ptac-GPPS-bLIS to produce linalool. The vector of the part is pR6K, with the promoter ptac, and composite part GPPS-bLIS. We first amplified the gene fragments using PCR (figure 3A, B, C and D) , and purified them to get pure gene fragments for pR6K-ptac-GPPS and bLIS.
Gibson assembly was used to create plasmid pR6K-patc-GPPS-bLIS. We transformed the pR6K-patc-GPPS-bLIS to E. Coli DH5 α. The success of transformation is verified by a colony PCR. And induced it with IPTG, which allows it to produce linalool synthase (figure.4)
However, pR6K-patc-GPPS-bLIS alone in the E. Coli can’t produce linalool, because the substrate of GPP synthase, DMPP, is produced by MVA pathway, so we also constructed a plasmid p15A-MVA (figure 5), which allows the bacteria to have MVA pathway in it and produce DMPP, so that linalool synthesize can be achieved.
We cotransformed P15A-MVA and pR6K-ptac-GPPS-bLIS plasmid to E.coli DH5α. We induced them with IPTG and two of them with extra glucose. After the inducing process, the bacteria solution was treated with n-hexane to extract purified linalool(figure 6). We can clearly smell the strong fragrance of linalool in those samples, and samples with glucose have a stronger fragrance than samples that are not treated with glucose. This indicates that glucose may promote the synthesis of linalool in E.coli DH5α. We do not need to knock out the gene in E.colii producing stinky smell because the aroma overcomes the smell of E.coli. Therefore, our E.coli won’t affect the local environment and appearance.
Besides, we also compared the smell of our sample to standard linalool sample, and standard geraniol, which is the product of pR6K-pTAC-GPPS-GES (the plasmid before our improvement) Based on our observation the aroma of geraniol contains sweetness; whereas, the aroma of standard linalool sample has a slight peppery smell. The two smells are quite distinguishable. The small of our samples also have a slightly peppery aroma, which is close to the linalool standard sample. Thus, we have successfully produced linalool.
In addition, through visual observation, we also confirmed that glucose can promote the synthesis of linalool in E.coli. The transparent liquids in the test tubes are purified linalool (figure 6). The volume of the liquid in samples treated with glucose is larger than samples that aren’t treated by glucose. Therefore, E.coli treated with glucose may be able to produce more linalool in the same condition than E.coli that is not. Our next step may be finding the optimal condition for linalool synthesis in E.coli. However, due to the Covid-19 situation, we do not have enough time in the lab, so we can only do those experiments in the future.